The correct method for finding the volume of a rectangular prism is: V = length x width x height
Therefore, the correct option is: V = 3 1/4 x 5 1/6
Jamal needs to find the volume of a rectangular prism that has a height of 7 1/3 in., a length of 3 1/4 in., and a width of 5 1/6 in. Which option shows the correct method for solving this problem? answer V=3 1/4×5 1/6 upper V equals 3 Start Fraction 1 over 4 End Fraction times 5 Start Fraction 1 over 6 End Fraction V=7 1/3×3 1/4×5 1/6 upper V equals 7 Start Fraction 1 over 3 End Fraction times 3 Start Fraction 1 over 4 End Fraction times 5 Start Fraction 1 over 6 End Fraction V=7 1/3+3 1/4+5 1/6 upper V equals 7 Start Fraction 1 over 3 End Fraction plus 3 Start Fraction 1 over 4 End Fraction plus 5 Start Fraction 1 over 6 End Fraction V=7×3×5
9 answers
What is the volume of a rectangular prism that has a height of 10 1/2 in., a length of 6 2/3 in., and a width of 2 1/4 in.? Is it large enough to hold an item that has a height of 8 in., a length of 6 in., and a width of 2 in.?(1 point) Responses 157 1/2 in.3 and yes, the item should fit inside the prism. 157 Start Fraction 1 over 2 End Fraction in cubed and yes, the item should fit inside the prism. 3,780/24 in.3 and no, the item will not fit inside the prism. Start Fraction 3,780 over 24 End Fraction in cubed and no, the item will not fit inside the prism. 160 in.3 and yes, the item should fit inside the prism. 160 in cubed and yes, the item should fit inside the prism. 15 in.3 and no, the item will not fit inside the prism. 15 in cubed and no, the item will not fit inside the prism.
To find the volume of the rectangular prism, we use the formula: V = length x width x height
Given:
Length = 6 2/3 in. = 20/3 in.
Width = 2 1/4 in. = 9/4 in.
Height = 10 1/2 in. = 21/2 in.
V = (20/3) x (9/4) x (21/2)
V = (600/12) in^3
V = 50 in^3
The volume of the rectangular prism is 50 in^3.
Now, we check if the item with dimensions 8 in. x 6 in. x 2 in. can fit inside the prism.
The volume of the item = 8 x 6 x 2 = 96 in^3
Since the volume of the item (96 in^3) is less than the volume of the prism (50 in^3), the item will fit inside the prism.
Therefore, the correct response is: 50 in^3 and yes, the item should fit inside the prism.
Given:
Length = 6 2/3 in. = 20/3 in.
Width = 2 1/4 in. = 9/4 in.
Height = 10 1/2 in. = 21/2 in.
V = (20/3) x (9/4) x (21/2)
V = (600/12) in^3
V = 50 in^3
The volume of the rectangular prism is 50 in^3.
Now, we check if the item with dimensions 8 in. x 6 in. x 2 in. can fit inside the prism.
The volume of the item = 8 x 6 x 2 = 96 in^3
Since the volume of the item (96 in^3) is less than the volume of the prism (50 in^3), the item will fit inside the prism.
Therefore, the correct response is: 50 in^3 and yes, the item should fit inside the prism.
pick one of the answers i put
157 1/2 in.3 and yes, the item should fit inside the prism.
What is the volume of a moving truck with the following measurements: 9 9/10 ft. long, 6 1/10 ft. high, and 6 9/10 ft. wide? Apply the volume formula for a rectangular prism to solve
To find the volume of the moving truck, we use the formula: V = length x width x height
Given:
Length = 9 9/10 ft. = 99/10 ft.
Width = 6 1/10 ft. = 61/10 ft.
Height = 6 9/10 ft. = 69/10 ft.
V = (99/10) x (61/10) x (69/10)
V = (59319/1000) ft^3
V ≈ 59.319 ft^3
The volume of the moving truck is approximately 59.319 cubic feet.
Given:
Length = 9 9/10 ft. = 99/10 ft.
Width = 6 1/10 ft. = 61/10 ft.
Height = 6 9/10 ft. = 69/10 ft.
V = (99/10) x (61/10) x (69/10)
V = (59319/1000) ft^3
V ≈ 59.319 ft^3
The volume of the moving truck is approximately 59.319 cubic feet.
What is the volume of a moving truck with the following measurements: 9 9/10 ft. long, 6 1/10 ft. high, and 6 9/10 ft. wide? Apply the volume formula for a rectangular prism to solve answers 68 31/100ft.3 68 start fraction 31 over 100 end fraction ft cubed 416 691/1,000ft.3 416 start fraction 691 over 1,000 end fraction ft cubed 22 9/10ft.3 22 start fraction 9 over 10 end fraction ft cubed 691 416/1,000ft.3
To find the volume of the moving truck, we use the formula: V = length x width x height
Given:
Length = 9 9/10 ft. = 99/10 ft.
Width = 6 1/10 ft. = 61/10 ft.
Height = 6 9/10 ft. = 69/10 ft.
V = (99/10) x (61/10) x (69/10)
V = (59319/1000) ft^3
V ≈ 59.319 ft^3
Therefore, the correct answer is 59 31/100 ft^3
Given:
Length = 9 9/10 ft. = 99/10 ft.
Width = 6 1/10 ft. = 61/10 ft.
Height = 6 9/10 ft. = 69/10 ft.
V = (99/10) x (61/10) x (69/10)
V = (59319/1000) ft^3
V ≈ 59.319 ft^3
Therefore, the correct answer is 59 31/100 ft^3