To solve this problem, you can use arithmetic progression formula:
S = n/2(2a + (n-1)d)
Where S is the total number of toys assembled, n is the number of days worked (20 in this case), a is the number of toys assembled on the first day (unknown), and d is the daily increase in the number of toys assembled (3 in this case).
To solve for a, you can use the information given on the 20th day:
137 = a + (20-1)3
137 = a + 57
a = 137 - 57
a = 80
Now that you have a, you can plug it into the formula to find S:
S = 20/2(2x80 + (20-1)3)
S = 10(160 + 57x19)
S = 10(160 + 1083)
S = 10(1243)
S = 12,430
Therefore, Jamal assembled a total of 12,430 toys during his first 20 days of work.
Jamal got a job working on a assembly line in a toy factory, on the 20th day of work, he assembled 137 toys, he noticed that since he started , every day he assembed 3 more toys then the day before , how many toys did jamal assemble all together during his first 20 days
can someone explain the steps to how to do this problem i am trying to do it on a google sheet
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