Jamaal can make 20 different combinations of 3 pairs of swim trunks.
To see why, we can use the formula for combinations, which is:
nCr = n! / r!(n-r)!
where n is the total number of items, r is the number of items to choose, and ! means factorial (the product of all positive integers up to that number).
In this case, n = 6 (the number of pairs of trunks that Jamaal has) and r = 3 (the number of pairs he needs to choose). So we can plug these values into the formula:
6C3 = 6! / 3!(6-3)!
= (6 x 5 x 4) / (3 x 2 x 1)
= 20
Therefore, Jamaal can make 20 different combinations of 3 pairs of swim trunks for his beach vacation.
Jamaal is heading to the beach for a vacation next week, and its time to pack. He has 6 pairs of swim trunks, but hell only need 3 for the trip. How many aitterent combinations of 3 pairs of trunks can he make?
1 answer