Asked by Joe
Jake needs to catch 1 10 pound fish to last 5 days. He catches 2 3.33 pound fish, 1 2.11 pound, and 1 1 pound fish. How long will he survive with that amount of food?
Answers
Answered by
bobpursley
He eats 2 lb/day.
time to last=lbs/rate=(6,66+2.11+1)/2 days
time to last=lbs/rate=(6,66+2.11+1)/2 days
Answered by
Henry
Total = 23*33 + 12*11 + 1*1 = 892 Lbs.
892Lbs * 5days/10Lbs = 446 Days.
892Lbs * 5days/10Lbs = 446 Days.
Answered by
Henry
Oops! I misread the numbers.
Total=2*3.33 + 1*2.11 + 1*1 = 9.77 Lbs.
9.77Lbs * 5days/10Lbs. = 4.9 Days or 5
days.
Total=2*3.33 + 1*2.11 + 1*1 = 9.77 Lbs.
9.77Lbs * 5days/10Lbs. = 4.9 Days or 5
days.
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