To solve \( 16 \times 16 \), we'll break it down step by step and fill in Jade's missing work.
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First, compute the units place:
- \( 6 \times 6 = 36 \)
- Write down 6 in the units place and carry over 3.
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Now move to the tens place:
- \( 1 \times 6 = 6 \) (adding the carryover, \( 6 + 3 = 9 \))
- So, write down 9 next to the 6.
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Now compute the next row (which is \( 16 \times 10 \)):
- The calculation involves \( 16 \) (from \( 16 \times 10 \)):
- Write down \( 1 (tens) \) and \( 6 (units) \), but since we are multiplying by 10, we perform the multiplication directly.
- This means we shift to the left by one place, giving us \( 160 \).
Putting it all together, the completed multiplication looks like this:
1 6
× 1 6
___________
6 6 (6 × 16)
+ 1 6 0 (16 × 10)
___________
2 5 6
Thus, the output for Jade's work would be filled as follows:
1 6
× 1 6
___________
+ 1 6 0
The answer \( 16 \times 16 = 256 \). So, the digits filled in for the missing work are:
- First row: \( 6 \) in the unit's place and \( 9 \) in the ten's place (implying carryover).
- Second row: \( 1 \) for the hundred's place (from 160).
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