Jada throws a rock horizontally from a bridge 32 m above the water, which hits the water approximately 25 m from a point immediantly below the bridge. Show that Jade's tossing speed was about 10 m/s.

Answer 1

h = Vo*t + 0.5g*t^2 = 32 m.
0 + 4.9t^2 = 32
t^2 = 6.53
Tf = 2.56 s. = Fall time.

Range = Xo * Tf = 25 m.
Xo * 2.56 = 25
Xo = 9.8 m/s. = Initial hor. velocity.