To solve this problem, let's first summarize what we know:
- Jada wants to do at least 100 push-ups in total for the week.
- She does 30 push-ups on Sunday.
- She plans to do the same number of push-ups each day for the remaining 6 days of the week (Monday to Saturday).
Let \( x \) be the number of push-ups she does each day from Monday to Saturday.
The total number of push-ups she will do for the week can be expressed as:
\[ 30 + 6x \]
To meet her goal of at least 100 push-ups, we can set up the following inequality:
\[ 30 + 6x \geq 100 \]
Now, we will solve the inequality for \( x \):
- Subtract 30 from both sides:
\[ 6x \geq 70 \]
- Divide both sides by 6:
\[ x \geq \frac{70}{6} \]
Simplifying \( \frac{70}{6} \) gives:
\[ x \geq \frac{35}{3} \approx 11.67 \]
Since Jada can't do a fraction of a push-up, we will round up to the nearest whole number. Therefore:
\[ x \geq 12 \]
This means Jada needs to do at least 12 push-ups each day for the rest of the week to meet her goal.
Now, let's look at the interpretation choices. The correct interpretation is:
Jada needs to do at least 12 push-ups each day for the rest of the week to meet her goal.