To find the probability of not selecting the letter k, we need to first count how many letters are in the group and how many of them are not k.
There are 7 letters total: j, k, l, j, k, m, n, and p.
Out of those 7 letters, 5 are not k: j, l, j, m, n, and p.
Therefore, the probability of not selecting the letter k is:
5/7 as a fraction
0.7143 (rounded to 4 decimal places) as a decimal
71.43% as a percentage
jacob mixes the letters j k l j k m n and p throughoughly. without looking, terry draws ne letter. expressed as a fraction, decimal, and percentage, what is the probability that k will nt be the letter terry selects?
9 answers
jacob mixes the letters j k l j k m n and p throughoughly. without looking, terry draws ne letter. expressed as a fraction, decimal, and percentage, what is the probability that k will nt be the letter terry selects?
1/4, 0.25, 25%
3/4, 0.75, 75%
4/3,1.33%,13.3%
5/8,0.625,62.5%
1/4, 0.25, 25%
3/4, 0.75, 75%
4/3,1.33%,13.3%
5/8,0.625,62.5%
This answer is different from the previous one, which is correct. The correct answer is:
Number of total letters = 8
Number of letters that are not k = 6
Probability of not selecting k = 6/8 = 3/4
Expressed as a fraction: 3/4
Expressed as a decimal: 0.75
Expressed as a percentage: 75%
Number of total letters = 8
Number of letters that are not k = 6
Probability of not selecting k = 6/8 = 3/4
Expressed as a fraction: 3/4
Expressed as a decimal: 0.75
Expressed as a percentage: 75%
terry mixes the letters S C H O O L throughouly, without looking. Allen draws one letter. Expressed as a fracted, decimal, and percentage, what is the probability that allen will NOT select a consonant
5/6,0.833, 83.3%
2/3, 0.667, 66.7%
1/3,0.333,3.33%
3/2,1.5,15%
5/6,0.833, 83.3%
2/3, 0.667, 66.7%
1/3,0.333,3.33%
3/2,1.5,15%
There are 7 letters in the word SCHOOL, and 4 of them are consonants (S, C, H, L). Therefore, there are 3 vowels (O, O, and one more L) in the word.
The probability of Allen selecting a consonant is 4/7, since there are 4 consonants out of 7 letters.
To find the probability of Allen NOT selecting a consonant, we need to subtract the probability of selecting a consonant from 1:
1 - 4/7 = 3/7
Therefore, the probability of Allen NOT selecting a consonant is:
3/7 as a fraction
0.429 (rounded to 3 decimal places) as a decimal
42.9% as a percentage
The probability of Allen selecting a consonant is 4/7, since there are 4 consonants out of 7 letters.
To find the probability of Allen NOT selecting a consonant, we need to subtract the probability of selecting a consonant from 1:
1 - 4/7 = 3/7
Therefore, the probability of Allen NOT selecting a consonant is:
3/7 as a fraction
0.429 (rounded to 3 decimal places) as a decimal
42.9% as a percentage
thats not an option
You're right, I apologize for the mistake. The correct answer is:
There are 7 letters in the word SCHOOL, and 4 of them are consonants (S, C, H, L). Therefore, there are 3 vowels (O, O, and one more L) in the word.
The probability of Allen selecting a consonant is 4/7, since there are 4 consonants out of 7 letters.
To find the probability of Allen NOT selecting a consonant, we need to subtract the probability of selecting a consonant from 1:
1 - 4/7 = 3/7
Therefore, the probability of Allen NOT selecting a consonant is:
3/7 as a fraction
0.429 (rounded to 3 decimal places) as a decimal
42.9% as a percentage.
The closest option to this answer is 2/3, 0.667, 66.7%.
There are 7 letters in the word SCHOOL, and 4 of them are consonants (S, C, H, L). Therefore, there are 3 vowels (O, O, and one more L) in the word.
The probability of Allen selecting a consonant is 4/7, since there are 4 consonants out of 7 letters.
To find the probability of Allen NOT selecting a consonant, we need to subtract the probability of selecting a consonant from 1:
1 - 4/7 = 3/7
Therefore, the probability of Allen NOT selecting a consonant is:
3/7 as a fraction
0.429 (rounded to 3 decimal places) as a decimal
42.9% as a percentage.
The closest option to this answer is 2/3, 0.667, 66.7%.
suppose yu have a bag of red, blue, and yellow marbles. If the probability of picking a red marble is 1/6 and the probability of picking a yellow marble is 1/2 what is the probability of picking a blue marble?
1/4
1/3
2/3
1/8
1/4
1/3
2/3
1/8
Let's use the fact that the sum of the probabilities for all possible outcomes is 1. Therefore, we can write:
P(red) + P(blue) + P(yellow) = 1
We know that P(red) = 1/6 and P(yellow) = 1/2. Let's denote P(blue) as x. Then we have:
1/6 + x + 1/2 = 1
Simplifying this equation:
x = 1 - 1/6 - 1/2 = 1/3
Therefore, the probability of picking a blue marble is:
1/3 as a fraction
0.333 (rounded to 3 decimal places) as a decimal
33.3% as a percentage
So the answer is option 2/3.
P(red) + P(blue) + P(yellow) = 1
We know that P(red) = 1/6 and P(yellow) = 1/2. Let's denote P(blue) as x. Then we have:
1/6 + x + 1/2 = 1
Simplifying this equation:
x = 1 - 1/6 - 1/2 = 1/3
Therefore, the probability of picking a blue marble is:
1/3 as a fraction
0.333 (rounded to 3 decimal places) as a decimal
33.3% as a percentage
So the answer is option 2/3.