Jackson has a box of markers. The box has 5 green markers, 2 red markers, 4 yellow markers, 3 blue markers, and 1 black marker. He randomly pulls 7 markers from the box and gets the following markers: yellow, blue, yellow, green, green, green, and black. what is the probability of Jackson not getting the black marker? enter your answer as a fraction.

Answer 1

First, we need to find the total number of ways Jackson can pull 7 markers from the box:

Total ways = (5 green markers) * (2 red markers) * (4 yellow markers) * (3 blue markers) * (1 black marker)
Total ways = 5 * 4 * 3 * 2 * 1 = 120

Next, we need to find the number of ways Jackson can pull 7 markers without the black marker:

Ways without black marker = (5 green markers + 2 red markers + 4 yellow markers + 3 blue markers) choose 7
Ways without black marker = (14 markers) choose 7 = 14C7 = 3432

Now, we can find the probability of Jackson not getting the black marker:

Probability = Ways without black marker / Total ways
Probability = 3432 / 120 = 1716 / 60 = 286 / 10 = 143 / 5

Therefore, the probability of Jackson not getting the black marker is 143/5.

Answer 2

wrong

Answer 3

I apologize for the error. Let's correct it:

The number of ways Jackson can pull 7 markers from the box without the black marker is the same as the number of ways he can pull 6 markers from the box, skipping the black marker.

Total ways = (5 green markers + 2 red markers + 4 yellow markers + 3 blue markers)
Total ways = 5 + 2 + 4 + 3 = 14

So, the number of ways Jackson can pull 6 markers without the black marker is:

Ways without black marker = (14 markers) choose 6
Ways without black marker = 14C6 = 3003

Now, we can find the probability of Jackson not getting the black marker:

Probability = Ways without black marker / Total ways
Probability = 3003 / 120 = 2503 / 1000 = 91 / 36

Therefore, the probability of Jackson not getting the black marker is 91/36.