To find out how far from Jackie the ball landed, we need to find the x-coordinate of the vertex of the parabola represented by the equation y=-0.05x^2+0.75x+5.
The x-coordinate of the vertex of a parabola in the form y=ax^2+bx+c is given by x=-b/2a.
In this case, a=-0.05 and b=0.75. Therefore, the x-coordinate of the vertex is x=-0.75/(2*(-0.05))=-0.75/(-0.1)=7.5.
So, the ball lands 7.5 feet away from Jackie.
Jackie, who is 5 feet tall, throws a football into the air as if she were throwing it to someone. The path of the football can be expressed by the equation y=−0.05x2+0.75x+5. Solve as if you were to graph the parabola to figure out how far from Jackie the ball landed.
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