d1 = d2
0.5a*t^2 = 25t
0.5a*t = 25
0.5*0.004t = 25
t = 12,500 s. = 3.5 h.
Jack is driving with a pail of water along a straight pathway at a steady 25 m/s when he passes Jill who is parked in her minivan waiting for him. When Jack is beside Jill, she begins accelerating at the rate of 4.0 × 10−3 m/s2 in the same direction that Jack is driving. How long does it take Jill to catch up to Jack?
2 answers
@Henry og bOI