Jack flew home for Christmas. His flight was 2 hours and 14 minutes. The flight landed in Jacksonville at 5:15 p.m. It took him 37 minutes to drive to the airport, and he was an hour and 10 minutes early for his flight. At what time did he leave his house?

Answer 1

It took him 37 minutes to drive to the airport and he was an hour and 10 minutes early for his flight, so he spent 37 + 70 = <<37+70=107>>107 minutes traveling to the airport.
The flight was 2 hours and 14 minutes, so he spent 2 + 14/60 = 2.23 hours flying.
Since there are 60 minutes in an hour, 2.23 hours is equal to 2.23 * 60 = <<2.23*60=133.8>>133.8 minutes.
So it took him 107 + 133.8 = <<107+133.8=240.8>>240.8 minutes in total to get to the airport and fly to Jacksonville.
He landed in Jacksonville at 5:15 p.m., so he left his house 240.8 minutes earlier, at 5:15 - 240.8/60 = <<5.15-240.8/60=0.457>>0.457 hours earlier.
There are 60 minutes in an hour, so 0.457 hours is equal to 0.457 * 60 = 27.4 minutes earlier.
Therefore, he left his house at 5:15 - 27.4 = 4:47 p.m.