assistance needed
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I've tried for hours to solve for v, but can't get the rearranging right.
I'm using
L= Lo sqrt 1- v^2/c^2
Can anyone suggest the first couple of steps?
I can get the answer by the way, by substituting values 'til I get the contracted length. Original and final length are given.
Thanks
2 answers
I am not familiar with this formula, but I can help with the manipulation.
L= Lo sqrt 1- v^2/c^2 or
L= Lo √( 1- v^2/c^2)
square both sides
L^2 = (Lo)^2(1-v^2/c^2)
L^2/(Lo)^2 = 1 - v^2/c^2
multiply both sides by c^2
c^2L^2/(Lo)^2 = c^2 - v^2
rearrange:
v^2 = c^2 - c^2L^2/(Lo)^2
v = √[c^2 - c^2L^2/(Lo)^2]
actually v would be +/- but I would guess you only wanted the positive result of v
L= Lo sqrt 1- v^2/c^2 or
L= Lo √( 1- v^2/c^2)
square both sides
L^2 = (Lo)^2(1-v^2/c^2)
L^2/(Lo)^2 = 1 - v^2/c^2
multiply both sides by c^2
c^2L^2/(Lo)^2 = c^2 - v^2
rearrange:
v^2 = c^2 - c^2L^2/(Lo)^2
v = √[c^2 - c^2L^2/(Lo)^2]
actually v would be +/- but I would guess you only wanted the positive result of v
1 answer