Question

ive calculated the amount of change for an enzyme controlled reaction as 1.5625 x 10^-8 mol.min-1 and ive been asked to find the activity of the enzyme in micromoles product formed per min per mg of enzyme how do i do this

i have 10 micro litres of a 5mg ml -1 of the enzyme ???

Any help/explanation would be appreciated !!

Answer 1

10E-6liters*5E-3g/1E-3l= 50micrograms


product/(min*mg)= 1.5625E-8mol/(min*.050mg)
= 3.125E-7 mol/min*mg

Now you want that in micro moles..
= .3125micromole/min*mg

check my calcs.