Let x be the time in seconds it takes for the torpedo to catch up to the ship.
Distance of ship = speed of ship x time taken = 35x
Distance of torpedo = speed of torpedo x time taken = 65x
Since they meet in 180 seconds:
35(180) + 65(180) = 65x + 35x
6300 = 100x
x = 63
Therefore, it will take the torpedo 63 seconds to catch up to the ship.
it was only 180 seconds after the ship passed the submarine (thinking it was a friend) that the submarine fired a torpedo at it. If the ship is traveling at 35 feet per second and the torpedo is chasing it at 65 feet per second, how many seconds will it take the torpedo to catch the ship?
( the answer is not 390 seconds)
*the submarine's distance has to equal the ship's distance. And remember, distance equals speed multiplied by time.*
11 answers
omg u stupid the answer is 210 seconds
I apologize for the mistake in my calculation. Let me re-calculate it.
35(180) + 65(180) = 65x + 35x
6300 = 100x
x = 63
My previous calculation was correct and the answer is indeed 63 seconds. Thank you for pointing out the mistake.
35(180) + 65(180) = 65x + 35x
6300 = 100x
x = 63
My previous calculation was correct and the answer is indeed 63 seconds. Thank you for pointing out the mistake.
the answer is 210 seconds. You're incorrect.
Let's reassess the calculation:
The ship is traveling at 35 feet per second for 180 seconds before the torpedo is fired.
Distance traveled by the ship = 35 feet/second x 180 seconds = 6300 feet
The torpedo is chasing the ship at 65 feet per second.
Let the time for the torpedo to catch up be t seconds.
Distance traveled by the torpedo = 65 feet/second x t seconds
Since the distances are equal when the torpedo catches up:
65t = 6300
t = 6300 / 65
t = 96.92 seconds
Therefore, it will take the torpedo approximately 96.92 seconds to catch up with the ship, which is closer to 97 seconds rather than 210 seconds.
The ship is traveling at 35 feet per second for 180 seconds before the torpedo is fired.
Distance traveled by the ship = 35 feet/second x 180 seconds = 6300 feet
The torpedo is chasing the ship at 65 feet per second.
Let the time for the torpedo to catch up be t seconds.
Distance traveled by the torpedo = 65 feet/second x t seconds
Since the distances are equal when the torpedo catches up:
65t = 6300
t = 6300 / 65
t = 96.92 seconds
Therefore, it will take the torpedo approximately 96.92 seconds to catch up with the ship, which is closer to 97 seconds rather than 210 seconds.
you think you're smarter than me?
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no you stupid i'm launching a nuke at your headquarters. the answer is 210 seconds
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im concerned.. Were you dropped on your head as a fetus?
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