To find out how many more hours Victor spent on his science project compared to his art project, we need to subtract the time he spent on the art project from the time he spent on the science project.
First, let's convert the mixed numbers into improper fractions.
-
Science Project: \[ 8 \frac{4}{5} = \frac{8 \times 5 + 4}{5} = \frac{40 + 4}{5} = \frac{44}{5} \]
-
Art Project: \[ 5 \frac{3}{10} = \frac{5 \times 10 + 3}{10} = \frac{50 + 3}{10} = \frac{53}{10} \]
Now we have:
- Science Project: \(\frac{44}{5}\)
- Art Project: \(\frac{53}{10}\)
Next, we need to find a common denominator to subtract these fractions. The least common multiple (LCM) of 5 and 10 is 10.
Now convert \(\frac{44}{5}\) to have a denominator of 10: \[ \frac{44}{5} = \frac{44 \times 2}{5 \times 2} = \frac{88}{10} \]
Now we can perform the subtraction: \[ \frac{88}{10} - \frac{53}{10} = \frac{88 - 53}{10} = \frac{35}{10} = \frac{7}{2} = 3 \frac{1}{2} \]
Therefore, Victor spent \(3 \frac{1}{2}\) hours more on his science project than on his art project.