Q = mc(T2-T1)
where Q = heat in J, m = mass in kg, c = specific heat capacity in J/(g*K), T = temperature in Kelvin,,
**change in temperature can have unit degree Celsius or Kelvin,, thus you can use it interchangeably (what i mean is that the units for c can also be J/(g*C))
therefore:
51 = 8.6*c*(25-13)
c = 0.494 J/g*K
(always check significant figures)
so there,, :)
It takes 51.0 j to raise the temperature of an 8.60 g piece of unknown metal from 13.0 C to 25.0 C. What is the specific heat for the metal?
2 answers
A 15.7g block of an unknown metal is warmed to 53.2o C and plunged into an insulated beaker containing 32.5g of water initially at 24.5o C. The metal block and water are allowed to come to thermal equilibrium and the final temperature of the system is 27.2oC. Assuming that no heat is lost, find the specific heat of the mystery metal block and specify the identity of the metal.