Ignoring dissipative losses (air resistance, friction, etc.),
difference of kinetic energy equals work done,
=>
(1/2)m(28.3^2-23.3^2)=226000 j
Solve for m.
It takes 226 kJ of work to accelerate a car from 23.3 m/s to 28.3 m/s. What is the car's mass?
1 answer