Work done equals the CHANGE in K.E.
Have you tried this:
(1/2)m*[27.8^2 - 23.7^2] = 164,000 ?
Solve for m. It should work.
It takes 164 kJ of work to accelerate a car from 23.7 m/s to 27.8 m/s. What is the car's mass?
I tried using this equation but it didn't work
KE = 1/2mv^2
2 answers
An antelope moving with constant acceleration covers the distance between two points 70.0
m apart in 7.00 s. Its speed as it passes the second point is 15.0 m/s. (a) What is its speed at the first
point? (b) What is its acceleration?
m apart in 7.00 s. Its speed as it passes the second point is 15.0 m/s. (a) What is its speed at the first
point? (b) What is its acceleration?
2 answers