To find the amount in the bank after 10 years of monthly deposits, we can use the formula for compound interest:
A = P(1 + r/n)^(nt)
Where:
A = the amount of money accumulated after time t
P = the initial deposit
r = the annual interest rate (in decimal form)
n = the number of times that interest is compounded per year
t = the number of years
In this case, the initial deposit is $100, the annual interest rate is 5% (or 0.05 in decimal form), and the interest is compounded monthly (so n = 12).
Using the given information, we have:
A = $100(1 + 0.05/12)^(12*10)
A = $100(1.00416666667)^(120)
A = $100(1.647009483)
A ≈ $164.70
Therefore, the amount after 10 years of monthly deposits is approximately $164.70 when rounded to the nearest cent.
To express this amount in the form a×10^n, we can convert it to scientific notation:
A = 1.647 × 10^2
Therefore, the amount $164.70 can be expressed in the form a×10^n as 1.647 × 10^2.
It takes 10 years for a $100 monthly bank deposit to amount to $15,528.23 when invested at 5% interest compounded monthly. Round to the nearest place value, then express the amount $15,528.23 in the form of a×10^n where a is single digit
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