It takes 1 molecule of nitrogen and 3

Question

molecules of hydrogen to produce 2
molecules of ammonia using the following formula:

1N2+ 3H2 → 2NH3

Identify which combination of molecules will produce ammonia with no leftovers?

(1 point)
Responses

4N2 and 4H2
4 n sub 2 and 4 h sub 2

2N2 and 6H2
2 n sub 2 and 6 h sub 2

8N2 and 4H2
8 n sub 2 and 4 h sub 2

5N2 and 6H2

Answer 1

To determine which combination of molecules will produce ammonia with no leftovers, we can look at the stoichiometry of the reaction:

\[ \text{1} \text{N}_2 + \text{3} \text{H}_2 \rightarrow \text{2} \text{NH}_3 \]

This means that:

• 1 molecule of N₂ reacts with 3 molecules of H₂ to produce 2 molecules of NH₃.

To analyze the provided options, we need to check each combination to see if they adhere to this stoichiometric balance:

1. 4N₂ and 4H₂:

   • N₂: 4
   • H₂ required: \( 4 \times 3 = 12 \)
   • Leftover H₂: \( 4 - 12 = -8 \) (deficit)

2. 2N₂ and 6H₂:

   • N₂: 2
   • H₂ required: \( 2 \times 3 = 6 \)
   • Produces \( 2 \times 2 = 4 \) NH₃ with no leftovers. This combination works perfectly.

3. 8N₂ and 4H₂:

   • N₂: 8
   • H₂ required: \( 8 \times 3 = 24 \)
   • Leftover H₂: \( 4 - 24 = -20 \) (deficit)

4. 5N₂ and 6H₂:

   • N₂: 5
   • H₂ required: \( 5 \times 3 = 15 \)
   • Leftover H₂: \( 6 - 15 = -9 \) (deficit)

From the calculations above, the only combination that produces ammonia without leftovers is:

2N₂ and 6H₂.