Question

It takes 1 molecule of nitrogen and 3 molecules of hydrogen to produce 2 molecules of ammonia using the following formula: 1N2+ 3H2 → 2NH3 Identify which combination of molecules will produce ammonia with no leftovers? (1 point) Responses 5N2 and 6H2 5 n sub 2 and 6 h sub 2 8N2 and 4H2 8 n sub 2 and 4 h sub 2 2N2 and 6H2 2 n sub 2 and 6 h sub 2 4N2 and 4H2 4 n sub 2 and 4 h sub 2

Answer 1

To determine which combination of molecules produces ammonia with no leftovers, we need to examine the stoichiometry of the reaction:

1 N₂ + 3 H₂ → 2 NH₃

This implies:

• 1 molecule of N₂ produces 2 molecules of NH₃ (requires 3 molecules of H₂)
• 3 molecules of H₂ are needed to react with 1 molecule of N₂

Now, let’s evaluate each option:

1. 5 N₂ and 6 H₂

   • N₂: 5 produces \(5 \times 2 = 10\) NH₃
   • H₂: 6 can produce \(6 / 3 = 2\) N₂ which requires \(6\) H₂, yielding only 4 NH₃.
   • Leftover: H₂ leftover because you can only produce 4 NH₃.

2. 8 N₂ and 4 H₂

   • N₂: 8 produces \(8 \times 2 = 16\) NH₃
   • H₂: 4 can produce \(4 / 3 \approx 1.33\) N₂ which is insufficient to use all N₂.
   • Leftovers: N₂ leftover.

3. 2 N₂ and 6 H₂

   • N₂: 2 produces \(2 \times 2 = 4\) NH₃.
   • H₂: 6 can produce \(6 / 3 = 2\) N₂ which requires \(6\) H₂, exactly enough for 4 NH₃.
   • No leftovers.

4. 4 N₂ and 4 H₂

   • N₂: 4 produces \(4 \times 2 = 8\) NH₃.
   • H₂: 4 can produce \(4 / 3 \approx 1.33\) N₂ which is insufficient to utilize all N₂.
   • Leftovers: N₂ leftover.

The only combination that exactly produces ammonia with no leftovers is: 2 N₂ and 6 H₂.