To produce ammonia (NH₃) using the reaction:
\[ N_2 + 3H_2 \rightarrow 2NH_3 \]
1 mole of nitrogen (N₂) reacts with 3 moles of hydrogen (H₂) to produce 2 moles of ammonia (NH₃).
To produce ammonia with no leftover reactants, you need to maintain the stoichiometric ratio from the equation, which means the combinations must follow the ratio of 1:3:2 for N₂:H₂:NH₃.
Here are a few combinations of molecules that will produce ammonia with no leftover reactants:
-
1 Mole N₂ + 3 Moles H₂:
- Produces 2 Moles NH₃
-
2 Moles N₂ + 6 Moles H₂:
- Produces 4 Moles NH₃
-
3 Moles N₂ + 9 Moles H₂:
- Produces 6 Moles NH₃
Any combination that maintains the ratio of 1 mole of N₂ to 3 moles of H₂ will yield ammonia without any leftover. For every mole of N₂, you must use exactly 3 moles of H₂. If you use different amounts, you must ensure they adhere to this ratio.