It keeps saying I am wrong!

Am I doing the math incorrectly?

Problem:
Calculate the amount of energy released in kJ/mol for the fusion reaction of two 1H atoms to yield a 2H atom and electron:
1/1H+1/1H→2/1H+0/1e
The atomic masses are
0/1e (0.0005486 u),
1H (1.00783 u),
2H (2.01410 u),
and 3He (3.01603 u).
....

2(1.00783u)= 2.01566u
2.01410 u + 0.0005486 u= 2.0146486u

Subtract for mass defect:
2.01566u-2.01566u=0.0010114u

Convert to kg:
(0.0010114u)(1.661e^-20kg) =3.46260494e^-12kg

E=mc^2:
E=(3.46260494e^-12kg)((2.998e^8m/s)^2)=
1699.19855J/atom

Convert to kJ/mol:
((1699.19855J/atom)(6.022e^23atoms/mol) /1000J)
=99714419144.9kJ/mol
or 9.971e^10kJ/mol

My answer:
E=9.971e^10kJ/mol
What did I do wrong?

3 answers

I didn't look at all of it but 1 amu = 1.6605E-27 kg
It still says that I have the wrong answer.

Using 1 amu = 1.6605E-27 kg I got
(0.0010114u)(1.6605e^-27kg) =3.1565365e^-15kg

(3.1565365e^-15kg)((2.998e^8m/s)^2)
=77.1202723J

((77.1202723J/atoms)(6.022e^23atoms/mol) /1000J)
=4525664853.4
or 4.526e^-9
So then E=4.526e^-9
Right?
From this step,
Using 1 amu = 1.6605E-27 kg I got
(0.0010114u)(1.6605e^-27kg) =3.1565365e^-15kg

I don't believe this math is correct. Estimate 1E-3*1.7E-27 = about 1.7E-30
Similar Questions
  1. Mr. Barkley's solutions are wrong!Determine the error which was made. Please be specific! In what step was the error? What was
    1. answers icon 6 answers
  2. Mr. Barkley's solutions are wrong!Determine the error which was made. Please be specific! In what step was the error? What was
    1. answers icon 3 answers
  3. Hi,How do I improve my math skills? I can't calculate in my head (I.e 2x43), I would actually have to write it down to solve it.
    1. answers icon 1 answer
    1. answers icon 2 answers
more similar questions