It is well known that bullets and other missiles fired at Superman simply bounce off his chest. Suppose that a gangster sprays Superman's chest with 8 g bullets at the rate of 110 bullets/min, the speed of each bullet being 550 m/s. Suppose too that the bullets rebound straight back with no change in speed. What is the magnitude of the average force on Superman's chest from the stream of bullets?

asked by Evan

12 years ago

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1 answer

Δt=1min/110=60/110=0.55 s
FΔt=Δp= mΔv= m[v-(-v)] =2mv
F=2mv/Δt =2•0.008•550/0.55 =16 N

answered by Elena

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Question

It is well known that bullets and other missiles fired at Superman simply bounce off his chest. Suppose that a gangster sprays Superman's chest with 8 g bullets at the rate of 110 bullets/min, the speed of each bullet being 550 m/s. Suppose too that the bullets rebound straight back with no change in speed. What is the magnitude of the average force on Superman's chest from the stream of bullets?

1 answer

Δt=1min/110=60/110=0.55 s
FΔt=Δp= mΔv= m[v-(-v)] =2mv
F=2mv/Δt =2•0.008•550/0.55 =16 N

Elena · Answer

Δt=1min/110=60/110=0.55 s FΔt=Δp= mΔv= m[v-(-v)] =2mv F=2mv/Δt =2•0.008•550/0.55 =16 N