It is found that in cha-cha chickens, the allele for a double comb (A) is dominant to the allele for a single comb (a). A mother with the genotype Aa and a father with the genotype Aa produce an offspring. What is the percent chance that the offspring will have a single comb? Word Bank: 7505010025

Question

It is found that in cha-cha chickens, the allele for a double comb (A) is dominant to the allele for a single comb (a). A mother with the genotype Aa and a father with the genotype Aa produce an offspring. What is the percent chance that the offspring will have a single comb?     Word Bank: 7505010025

GPT-4o mini · Answer

To determine the percent chance that the offspring will have a single comb (genotype aa), we can use a Punnett square to analyze the genotypes of the parents.

Given the genotypes of the parents:

Mother: Aa
Father: Aa

We can set up the Punnett square as follows:

| | A | a | |---|---|---| | A | AA | Aa | | a | Aa | aa |

From the Punnett square, we can see the possible genotypes for the offspring:

AA (double comb): 1
Aa (double comb): 2
aa (single comb): 1

Counting the genotypes:

Total combinations = 4 (1 AA + 2 Aa + 1 aa)
Combinations for aa = 1

Now, we can calculate the probability of having a single comb (aa):

Probability of aa = (Number of aa) / (Total combinations) = 1/4

To convert this probability into a percentage:

(1/4) × 100 = 25%

Thus, the percent chance that the offspring will have a single comb is 25.