It is equally probable that the pointer on the spinner shown will land on any one of the eight regions, numbered 1 through 8. If the pointer lands on a borderline, spin again. Find the probability that the pointer will stop on an odd number or a number less than 5.

Answer 1

There are 8 regions on the spinner, numbered 1 through 8.

Out of the eight regions, four of them are odd numbers: 1, 3, 5, and 7.

Out of the eight regions, four of them are less than 5: 1, 2, 3, and 4.

However, we need to subtract the regions that fall in both categories (below 5 and odd). The region that is both odd and less than 5 is 1, which we don't want to count twice.

So, the total number of favorable outcomes (odd or less than 5) is 4 + 4 - 1 = 7.

The total number of possible outcomes is 8.

Therefore, the probability that the pointer will stop on an odd number or a number less than 5 is 7/8.