It is believed that 60% of voters from a certain region in South Africa favour the free trade agreement. A recent poll indicated that out of 400 randomly selected individuals, 250 favoured the free trade agreement. Test at 5% significance level if indeed at least 60% of voters favoured the FTA. Make you decision.

1 answer

To test the hypothesis that at least 60% of voters favor the free trade agreement (FTA) based on the recent poll, we can perform a hypothesis test for proportions.

Step 1: State the null and alternative hypotheses.

  • Null Hypothesis (H0): \( p \geq 0.60 \) (At least 60% of voters favor the FTA)
  • Alternative Hypothesis (H1): \( p < 0.60 \) (Less than 60% of voters favor the FTA)

Step 2: Determine the sample proportion.

From the poll:

  • Sample size \( n = 400 \)
  • Number of individuals favoring the FTA \( x = 250 \)

The sample proportion \( \hat{p} \) is calculated as: \[ \hat{p} = \frac{x}{n} = \frac{250}{400} = 0.625 \]

Step 3: Calculate the test statistic.

We will use the formula for the test statistic for proportions: \[ z = \frac{\hat{p} - p_0}{\sqrt{\frac{p_0(1 - p_0)}{n}}} \] Where:

  • \( p_0 = 0.60 \) is the population proportion under the null hypothesis,
  • \( n = 400 \) is the sample size.

First, we calculate the standard error: \[ \text{Standard Error} = \sqrt{\frac{p_0(1 - p_0)}{n}} = \sqrt{\frac{0.60 \times (1 - 0.60)}{400}} = \sqrt{\frac{0.60 \times 0.40}{400}} = \sqrt{\frac{0.24}{400}} = \sqrt{0.0006} \approx 0.02449 \]

Now, substitute \( \hat{p} \), \( p_0 \), and the standard error into the z formula: \[ z = \frac{0.625 - 0.60}{0.02449} \approx \frac{0.025}{0.02449} \approx 1.0205 \]

Step 4: Determine the critical value and make a decision.

For a one-tailed test at a significance level of \( \alpha = 0.05 \), we look up the critical z-value:

  • The critical z-value for \( \alpha = 0.05 \) (one-tailed) is approximately -1.645 (since we are testing if the proportion is less than 0.60).

Now we compare our calculated z-value with the critical z-value:

  • Calculated z-value: \( z \approx 1.0205 \)
  • Critical z-value: -1.645

Step 5: Conclusion

Since \( z = 1.0205 \) is greater than -1.645, we do not reject the null hypothesis.

Final Decision

At the 5% significance level, there is insufficient evidence to conclude that less than 60% of voters favor the free trade agreement. Therefore, we accept the belief that at least 60% of voters favor the FTA based on the sample data.