take 5.6/2=2.8
convert 2.8miles into meters=4506
9.8/4506= .002174878
now squaroot that and you wil getthe answer which is
(.0466)
It has been suggested that rotating cylinders about 10 mi long and 5.6 mi in diameter be placed in space and used as colonies. What angular speed must such a cylinder have so that the centripetal acceleration at its surface equals the free-fall acceleration?
3 answers
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r=5.6/2 = 2.8mi
convert from mi to m use
imi= 1609.34m
2.8mi? =1609.34*2.8=4506.152m
g=v^2/r , g=9.8, making v subject we get
v^2= 9.8*4506.152
v=210.14m/s
but w=v/r
w= 210.14/4506.152=0.047rad/s
for help eseyhelp @ gmail com (no spaces)
convert from mi to m use
imi= 1609.34m
2.8mi? =1609.34*2.8=4506.152m
g=v^2/r , g=9.8, making v subject we get
v^2= 9.8*4506.152
v=210.14m/s
but w=v/r
w= 210.14/4506.152=0.047rad/s
for help eseyhelp @ gmail com (no spaces)