cost x = 1/8 * 192
of Ismail => 24
Jared = y Keith => 24 + y
24 + y + 24 + y = 192
Jared pay y = 72
Ismail, Jared and Keith shared the cost of a meal. Ismail paid 1/8 of the bill. Keith paid the same amount as the total sum paid by Ismail and Jared. If the cost of the meal was $192, how much did Jared pay for the meal?
2 answers
To solve this problem, we need to use algebra. Let's start by letting x be the amount that Jared paid for the meal. We know that Ismail paid 1/8 of the bill, which means that he paid:
1/8 * $192 = $24
We also know that Keith paid the same amount as the total sum paid by Ismail and Jared. So, the total amount paid by Ismail and Jared is:
$24 + x
Therefore, Keith paid:
$24 + x
And we know that the total cost of the meal was $192, so we can set up an equation:
$24 + x + $24 + x = $192
Simplifying this equation, we get:
2x + $48 = $192
Subtracting $48 from both sides, we get:
2x = $144
Dividing both sides by 2, we get:
x = $72
Therefore, Jared paid $72 for the meal.
1/8 * $192 = $24
We also know that Keith paid the same amount as the total sum paid by Ismail and Jared. So, the total amount paid by Ismail and Jared is:
$24 + x
Therefore, Keith paid:
$24 + x
And we know that the total cost of the meal was $192, so we can set up an equation:
$24 + x + $24 + x = $192
Simplifying this equation, we get:
2x + $48 = $192
Subtracting $48 from both sides, we get:
2x = $144
Dividing both sides by 2, we get:
x = $72
Therefore, Jared paid $72 for the meal.