Ismail, Jared and Keith shared the cost of a meal. Ismail paid 1/8 of the bill. Keith paid the same amount as the total sum paid by Ismail and Jared. If the cost of the meal was $192, how much did Jared pay for the meal?

Answer 1

cost x = 1/8 * 192
of Ismail => 24
Jared = y Keith => 24 + y
24 + y + 24 + y = 192
Jared pay y = 72

Answer 2

To solve this problem, we need to use algebra. Let's start by letting x be the amount that Jared paid for the meal. We know that Ismail paid 1/8 of the bill, which means that he paid:

1/8 * $192 = $24

We also know that Keith paid the same amount as the total sum paid by Ismail and Jared. So, the total amount paid by Ismail and Jared is:

$24 + x

Therefore, Keith paid:

$24 + x

And we know that the total cost of the meal was $192, so we can set up an equation:

$24 + x + $24 + x = $192

Simplifying this equation, we get:

2x + $48 = $192

Subtracting $48 from both sides, we get:

2x = $144

Dividing both sides by 2, we get:

x = $72

Therefore, Jared paid $72 for the meal.