To solve the problem involving Isaac's food truck selling tacos and burritos, we can start by establishing the inequalities based on the information provided.
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Total Supply Constraint: Isaac has enough supplies to make 130 tacos or burritos combined. If \(x\) represents the number of tacos sold and \(y\) represents the number of burritos sold, this can be represented as: \[ x + y \leq 130 \]
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Revenue Constraint: Isaac must sell at least $850 worth of tacos and burritos. The total revenue from tacos (at $4.25 each) and burritos (at $8.50 each) can be expressed as: \[ 4.25x + 8.50y \geq 850 \] To make the calculations easier, we can convert the prices into a more manageable whole number format by multiplying through by 4 (to eliminate decimal values): \[ 17x + 34y \geq 3400 \]
Now we have the following system of inequalities:
- \(x + y \leq 130\)
- \(17x + 34y \geq 3400\)
Finding Two Points for Each Inequality
For the Inequality \(x + y \leq 130\)
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x-intercept: Set \(y = 0\) \[ x + 0 = 130 \implies x = 130 \implies (130, 0) \]
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y-intercept: Set \(x = 0\) \[ 0 + y = 130 \implies y = 130 \implies (0, 130) \]
For the Inequality \(17x + 34y \geq 3400\)
First, we solve for the boundary line:
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Rearranging: \[ 17x + 34y = 3400 \implies y = \frac{3400 - 17x}{34} \]
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x-intercept: Set \(y = 0\) \[ 17x = 3400 \implies x = 200 \implies (200, 0) \]
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y-intercept: Set \(x = 0\) \[ 34y = 3400 \implies y = 100 \implies (0, 100) \]
Graphing the Inequalities
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Plot the points for \(x + y \leq 130\):
- Points: (130, 0) and (0, 130)
- The line will be solid because it includes \(=\).
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Plot the points for \(17x + 34y \geq 3400\):
- Points: (200, 0) and (0, 100)
- The line will be dashed indicating that it doesn't include \(=\).
Graphing Instructions
- Draw the line for \(x + y = 130\) and shade below it.
- Draw the line for \(17x + 34y = 3400\) and shade above it.
Finding a Solution
We can choose a point in the area where the shadings overlap. For example, let’s take the point \((100, 30)\):
- Check \(x + y \leq 130\): \[ 100 + 30 = 130 \quad \text{(satisfied)} \]
- Check \(17x + 34y \geq 3400\): \[ 17(100) + 34(30) = 1700 + 1020 = 2720 \quad \text{(not satisfied)} \]
Let's try \((70, 60)\):
- Check \(x + y \leq 130\): \[ 70 + 60 = 130 \quad \text{(satisfied)} \]
- Check \(17x + 34y \geq 3400\): \[ 17(70) + 34(60) = 1190 + 2040 = 3230 \quad \text{(not satisfied)} \]
Now let's try \((80, 50)\):
- Check \(x + y \leq 130\): \[ 80 + 50 = 130 \quad \text{(satisfied)} \]
- Check \(17x + 34y \geq 3400\): \[ 17(80) + 34(50) = 1360 + 1700 = 3060 \quad \text{(not satisfied)} \]
Let's try \((60, 70)\):
- Check \(x + y \leq 130\): \[ 60 + 70 = 130 \quad \text{(satisfied)} \]
- Check \(17x + 34y \geq 3400\): \[ 17(60) + 34(70) = 1020 + 2380 = 3400 \quad \text{(satisfied)} \]
Final Answer
One possible solution is \(x = 60\) (60 tacos) and \(y = 70\) (70 burritos). This satisfies both inequalities.