To determine if the equation is completely balanced, we need to check the number of atoms of each element on both sides of the equation:
Given equation: \[ 2C_8H_8 + 25O_2 \rightarrow 8CO_2 + 18H_2O \]
Counting the atoms:
-
Left side (reactants):
- Carbon (C): \( 2 \times 8 = 16 \)
- Hydrogen (H): \( 2 \times 8 = 16 \)
- Oxygen (O): \( 25 \times 2 = 50 \)
-
Right side (products):
- From \( 8CO_2 \):
- Carbon (C): \( 8 \)
- Oxygen (O): \( 8 \times 2 = 16 \)
- From \( 18H_2O \):
- Hydrogen (H): \( 18 \times 2 = 36 \)
- Oxygen (O): \( 18 \times 1 = 18 \)
- From \( 8CO_2 \):
Total on the right side:
- Carbon (C): \( 8 \)
- Hydrogen (H): \( 36 \)
- Oxygen (O): \( 16 + 18 = 34 \)
Summary of counts:
- For the left side:
- C: 16
- H: 16
- O: 50
- For the right side:
- C: 8
- H: 36
- O: 34
Now, comparing both sides:
- Carbon: 16 (left) vs 8 (right) - not equal
- Hydrogen: 16 (left) vs 36 (right) - not equal
- Oxygen: 50 (left) vs 34 (right) - not equal
Since the number of carbon, hydrogen, and oxygen atoms on both sides are not equal, we can conclude:
The correct answer is:
A. No, because the number of carbon, hydrogen & oxygen atoms on both sides of the equation are not equal.