is this correct?

Question

To solve for y in the equation 3y + x = 33, we need to isolate y. Here are the steps:
1. Subtract x from both sides of the equation: 3y = 33 - x
2. Now, we divide both sides by 3 to solve for y: y = 33 – x / 3
3. Now we substitute x = 5 into the equation: y = 33 – x / 3 = 28 / 3 ≈ 9.3333
Final Answer: When x = 5 ,the value of y is approximately 9.3333. Therefore, the final answer is:
y ≈ 9.3333

Answer 1

There is an issue in the way the equation was simplified in step 2. The expression you had after isolating \( y \) was not properly formatted.

Let’s go through the steps correctly to clarify:

1. Start with the equation: \[ 3y + x = 33 \]

2. Subtract \( x \) from both sides: \[ 3y = 33 - x \]

3. Divide both sides by 3 to solve for \( y \): \[ y = \frac{33 - x}{3} \]

Now substituting \( x = 5 \) into the equation: \[ y = \frac{33 - 5}{3} = \frac{28}{3} \approx 9.3333 \]

So the final answer is correct: When \( x = 5 \), the value of \( y \) is approximately \( 9.3333 \).

Make sure to properly format the equation during substitution to avoid confusion. Your final answer is correct: \( y \approx 9.3333 \).