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What is the standard cell potential?
Pb2+ (aq) + 2e- → Pb(s) -0.13V
Mn2+ (aq) + 2e- → Mn(s) -1.19V
Pb2+ (aq) + 2e- → Pb(s) -0.13V
Mn(s) → Mn2+ (aq) + 2e- +1.19V
The electrode potential for a given cell,
E = E_cathode - E_anode = -0.13 - (-1.19) = +1.06 V.
Is this correct? Thanks.
What is the standard cell potential?
Pb2+ ( aq ) + 2e „³ Pb (s) -0.13V
Mn2+ ( aq ) + 2e „³ Mn (s) -1.19V
Pb2+ ( aq ) + 2e „³ Pb (s) -0.13V
Mn (s) „³ Mn2+ ( aq ) + 2e ¡V +1.19V
The electrode potential for a given cell,
E = Ecathode ¡V Eanode = -0.13 ¡V(-1.19) = +1.06 V
I don't understand some of the symbols.
What is the standard cell potential?
Pb2+ ( aq ) + 2e „³ Pb (s) -0.13V
Mn2+ ( aq ) + 2e „³ Mn (s) -1.19V
Pb2+ ( aq ) + 2e „³ Pb (s) -0.13V
Mn (s) „³ Mn2+ ( aq ) + 2e ¡V +1.19V
The electrode potential for a given cell,
E = Ecathode ¡V Eanode = -0.13 ¡V(-1.19) = +1.06 V
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