Asked by Laynie
is there any way to know if its products or reactants..?
The equilibrium constant for the gas phase reaction
N2 (g) + 3H2 (g) (2 arrows: one to right, one to left.) 2NH3 (g)
is Keq = 4.34 × 10^-3 at 300°C. At equilibrium, __________.
A) reactants predominate
B) only reactants are present
C) roughly equal amounts of products and reactants are present
D) only products are present
E) products predominate
Answers
                    Answered by
            DrBob222
            
    yes.
Q = (NH3)^2/(N2)(H2)^3 = 4.34E-3
In general, A is true. For Q to be small, the numerator must be small and the denominator must be large. The only way you get that is for the products to be small and the reactants to be large(r).
It's easier to answer questions like this when the squared and cubed terms are missing (concns just to the first power) such as K = (A)/(B)(C); then only A would b true out of all of the possibilities given. B and D are never true. C is true, in the simpler K I mentioned above, when k = 1; it's tougher to work it out with the squared and cubed terms there. But you can make up a scenario where NH3 = 2 and (H2) + N2 = 2, then Q = 1/4 (1 for 1 of each, 1/4 for 2 of each, 1/9 for 3 of each, 1/16 for 4 of each etc BUT products are always decreasing with those numbers which still means products are less than reactants.
    
Q = (NH3)^2/(N2)(H2)^3 = 4.34E-3
In general, A is true. For Q to be small, the numerator must be small and the denominator must be large. The only way you get that is for the products to be small and the reactants to be large(r).
It's easier to answer questions like this when the squared and cubed terms are missing (concns just to the first power) such as K = (A)/(B)(C); then only A would b true out of all of the possibilities given. B and D are never true. C is true, in the simpler K I mentioned above, when k = 1; it's tougher to work it out with the squared and cubed terms there. But you can make up a scenario where NH3 = 2 and (H2) + N2 = 2, then Q = 1/4 (1 for 1 of each, 1/4 for 2 of each, 1/9 for 3 of each, 1/16 for 4 of each etc BUT products are always decreasing with those numbers which still means products are less than reactants.
                    Answered by
            Laynie
            
    i understand a lot better now, thank you. someone tried to explain about k=1 and i just got more confused. thank you for taking the time to explain.
    
                    Answered by
            Laynie
            
    I have another question, if Keg was negative would it make a difference?
    
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.