Is the vertex of the graph a maximum or a minimum?
(1 point)
maximum
minimum
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both
5 answers
It is not possible to determine from the information given.
THIS THING WONT LET ME GIVE YOU LINKS SO WHAT TF AM I SUPPPOSED TO DO???
I apologize for any inconvenience. Can you please provide more context or describe the graph in a different way so that I can assist you without the need for links?
A ball is thrown into the air with an initial upward velocity of 46 ft/s. Its height (h) in feet after t seconds
is given by the function . After how many seconds will the ball hit the ground?
(1 point)
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is given by the function . After how many seconds will the ball hit the ground?
(1 point)
3
4
5
6
Given that the height h in feet after t seconds is given by a function, we would need the function to determine the exact time it will hit the ground. However, if we make some assumptions and use a simplified model assuming the only force acting on the ball is gravity, then we can use the standard formula for the height of an object in free fall:
h(t) = -16t^2 + v0t + h0
where:
- h(t) is the height of the ball in feet at time t seconds
- v0 is the initial velocity (46 ft/s in this case)
- h0 is the initial height (we can assume the ball is thrown from the ground, so h0 is 0)
Setting h(t) = 0 (i.e. the moment when the ball hits the ground) and solving the resulting equation, we get:
-16t^2 + 46t = 0
Factoring out a t, we get:
t(-16t + 46) = 0
The solutions are t = 0 (which is the initial time the ball is thrown) and t = 46/16 = 2.875 seconds, which is closest to 3 seconds.
Therefore, the ball will hit the ground after approximately 3 seconds. So the answer is:
3
h(t) = -16t^2 + v0t + h0
where:
- h(t) is the height of the ball in feet at time t seconds
- v0 is the initial velocity (46 ft/s in this case)
- h0 is the initial height (we can assume the ball is thrown from the ground, so h0 is 0)
Setting h(t) = 0 (i.e. the moment when the ball hits the ground) and solving the resulting equation, we get:
-16t^2 + 46t = 0
Factoring out a t, we get:
t(-16t + 46) = 0
The solutions are t = 0 (which is the initial time the ball is thrown) and t = 46/16 = 2.875 seconds, which is closest to 3 seconds.
Therefore, the ball will hit the ground after approximately 3 seconds. So the answer is:
3