To determine if the point (2, 8) is a solution to the inequalities \( y > 6x - 4 \) and \( y \leq 3x + 2 \), we can substitute \( x = 2 \) and \( y = 8 \) into both inequalities.
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For the inequality \( y > 6x - 4 \): \[ 8 > 6(2) - 4 \] \[ 8 > 12 - 4 \] \[ 8 > 8 \] This is not true since \( 8 \) is not greater than \( 8 \).
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For the inequality \( y \leq 3x + 2 \): \[ 8 \leq 3(2) + 2 \] \[ 8 \leq 6 + 2 \] \[ 8 \leq 8 \] This is true since \( 8 \) is equal to \( 8 \).
Since the point (2, 8) satisfies one inequality but does not satisfy the other, it is not a solution to the simultaneous inequalities.
Therefore, the answer is 2 (no).
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