Asked by APpreciative student
is the limit as x approaches 0 of sin3x over 3x equal to zero?
thank you!
thank you!
Answers
Answered by
TutorCat
do you mean?
(sin3x)/3x
hint: L'Hopital's Rule
take the derivative of the numerator and denominator
& then plug in zero
(sin3x)/3x
hint: L'Hopital's Rule
take the derivative of the numerator and denominator
& then plug in zero
Answered by
APpreciative student
sorry--
basically
lim [sin 3x / 4x)
x-> 0
i multiplied& eventually got to
.75* lim (sin 3x / 3x)
x-> 0
so i figured since (lim (sinx/x)
x-> 0
was equal to zero, then
lim (sin3x/ 3x) also equaled 0
x-> 0
is that right? thank you
basically
lim [sin 3x / 4x)
x-> 0
i multiplied& eventually got to
.75* lim (sin 3x / 3x)
x-> 0
so i figured since (lim (sinx/x)
x-> 0
was equal to zero, then
lim (sin3x/ 3x) also equaled 0
x-> 0
is that right? thank you
Answered by
TutorCat
take the derivative of the numerator and denominator individually.
then, plug in zero for x.
sin3x
hint: chain rule
then, plug in zero for x.
sin3x
hint: chain rule
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