To check--differentiate the integral to see if you get the original equation.
I believe you are correct.
is the integral of xln(x)dx=
x^2/4(4ln(x)-4-2ln(x)+3)+C?
2 answers
You should simplify what you wrote. You have constants and terms in ln x that can be combined. If you do, you should end up with
x^2[(ln x)/2 - 1/4] + C
x^2[(ln x)/2 - 1/4] + C
1 answer