Is the following integral nonexistent?

integral from -1 to 1 of 3/ x^2)
"three over (x squared)"


Thank you very much for your help!

Answers

Answered by bobpursley
You have to look at the function at zero.

INT 3/x^2 dx= -3/x

what does that do at zero? So is the area under it a determinate number? (remember integral means area)
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