Is the equation (root(8, 4)) ^ - 24 * (sqrt(8)) ^ 16 = 8 ^ - 48 true or false? Select the response that correctly answers the question justification.

True. When the bases are multiplied, the exponents are also multiplied.

True, but the equation can be simplified further.

False, because the Negative Exponent Rule should be applied.

False, because the exponents should be added rather than multiplied.

1 answer

To evaluate the equation \((\sqrt[8]{4})^{-24} \cdot (\sqrt{8})^{16} = 8^{-48}\), let's simplify both sides step by step.

First, we can rewrite the roots and exponents using properties of exponents:

  1. \(\sqrt[8]{4} = 4^{1/8}\), so \((\sqrt[8]{4})^{-24} = (4^{1/8})^{-24} = 4^{-24/8} = 4^{-3}\).

  2. Next, \(\sqrt{8} = 8^{1/2}\), so \((\sqrt{8})^{16} = (8^{1/2})^{16} = 8^{16/2} = 8^8\).

Now, substituting back into the equation:

\[ (\sqrt[8]{4})^{-24} \cdot (\sqrt{8})^{16} = 4^{-3} \cdot 8^8 \]

On the right side of the equation, we have \(8^{-48}\). Now simplify \(8^8\) as \(8^8 = (2^3)^8 = 2^{24}\).

Since \(4 = 2^2\), we can also rewrite \(4^{-3}\):

\[ 4^{-3} = (2^2)^{-3} = 2^{-6} \]

Now we have:

\[ 2^{-6} \cdot 8^8 = 2^{-6} \cdot 2^{24} = 2^{-6 + 24} = 2^{18} \]

Now consider \(8^{-48}\):

\[ 8^{-48} = (2^3)^{-48} = 2^{-144} \]

Now comparing both sides gives:

\[ 2^{18} \neq 2^{-144} \]

Therefore, we conclude that the equation is false.

So the correct answer is:

False, because the Negative Exponent Rule should be applied.

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