To evaluate the expression \( 7^{-4} \cdot 7^3 \div \sqrt{49} \), let's break it down step by step.
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Calculate \( \sqrt{49} \): \[ \sqrt{49} = 7 \]
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Rewrite the expression: The expression now looks like: \[ 7^{-4} \cdot 7^3 \div 7 \]
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Apply the Product Property: We can combine the terms in the numerator: \[ 7^{-4} \cdot 7^3 = 7^{-4 + 3} = 7^{-1} \]
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Rewrite the division: The expression turns into: \[ \frac{7^{-1}}{7} = 7^{-1 - 1} = 7^{-2} \]
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Evaluate \( 7^{-2} \): \[ 7^{-2} = \frac{1}{7^2} = \frac{1}{49} \]
Now let's compare this result with \( 7 \). Clearly, \( \frac{1}{49} \) is not equal to \( 7 \).
Therefore, the statement is:
False. When applying the Quotient Property, the final exponent is not 1.