To determine if \( t = 29 \) is a solution to the equation \( 0 = \frac{t}{29} \), we can substitute \( t \) with 29:
\[ 0 = \frac{29}{29} \]
This simplifies to:
\[ 0 = 1 \]
Since \( 0 \neq 1 \), \( t = 29 \) is not a solution to the equation.
The answer is no.