Let's analyze each part of your question step by step:
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Square root of π²:
- The square root of π² is |π| (the absolute value of π).
- Since π is an irrational number, |π| is also irrational.
- Therefore, the square root of π² is irrational.
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9π:
- Here, 9 is a rational number and π is an irrational number.
- The product of a rational number (9) and an irrational number (π) is irrational.
- Thus, 9π is irrational.
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Adding them together (√(π²) + 9π):
- We have |π| (irrational) + 9π (irrational).
- The sum of two irrational numbers is not guaranteed to be irrational. It can be either rational or irrational depending on the specific numbers involved.
- In this case, |π| (which equals π) and 9π are both irrational, but their sum (π + 9π) simplifies to 10π.
- Since 10π is the product of an integer (10) and an irrational number (π), it is irrational.
Conclusion:
- The square root of π² is irrational.
- 9π is irrational.
- Their sum, |π| + 9π (which is 10π), is also irrational.