Is it possible to separate Bi, Cu and Ag from a mixture containing:

c(BiO+)=0,08M
c(Cu2+)=0,242M
c(Ag)=0,106M
c(HClO4)=1M

Eo Bi = 0,32 V, Eo Cu = 0,337 V, Eo = 0,792 V
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Using Nernst equation (E=E°-0,0592/n -logQ)
i see it's possible to separate Ag, but what about Bi and Cu? I suppose no.
I got
E(Cu)=0,319V
E(Bi)= 0,298V
1% Cu.... 2,42*10^-3
Inserting this in Nernst equation I get E=0,260V, which is already in a range for depositing Bi.

Is my way of thinking correct?

Thank you for your help.