no. Because , if it had a period, say k > 0, then that would mean that
e^(x+k) = e^x
e^x e^k = e^x
e^k = 1
k=0
But, we specified k > 0.
I mean, just look at the graph. Surely it is not periodic!
Now, if we use a complex number z, then it is true that e^z is periodic.
Is {e^x} periodic function?
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