To determine whether (7, 3) is a solution to the system of equations, we will substitute \(x = 7\) and \(y = 3\) into both equations and see if both equations are satisfied.
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For the first equation: \[ 3x + 2y = 5 \] Substitute \(x = 7\) and \(y = 3\): \[ 3(7) + 2(3) = 21 + 6 = 27 \] This does not equal 5. So (7, 3) is not a solution to the first equation.
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For the second equation: \[ -x + 6y = 11 \] Substitute \(x = 7\) and \(y = 3\): \[ -7 + 6(3) = -7 + 18 = 11 \] This does equal 11, so (7, 3) is a solution to the second equation.
Since (7, 3) does not satisfy the first equation, it is not a solution to the system of equations.
Therefore, the correct answer is: No, because the graphs don’t intersect at (7, 3).
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