To determine if (4, 3) is a solution to the inequality \(3x + y \geq 20\), we can substitute \(x = 4\) and \(y = 3\) into the inequality:
\[ 3(4) + 3 \geq 20 \]
Calculating the left side:
\[ 12 + 3 = 15 \]
Now we check the inequality:
\[ 15 \geq 20 \]
This statement is false. Therefore, the point (4, 3) is not a solution to the inequality \(3x + y \geq 20\).
So, the answer is no.