Is(4, 3)a solution to the inequality 3x + y ≥ 20?

Yes or no

47 answers

To determine if (4, 3) is a solution to the inequality \(3x + y \geq 20\), we can substitute \(x = 4\) and \(y = 3\) into the inequality:

\[ 3(4) + 3 \geq 20 \]

Calculating the left side:

\[ 12 + 3 = 15 \]

Now we check the inequality:

\[ 15 \geq 20 \]

This statement is false. Therefore, the point (4, 3) is not a solution to the inequality \(3x + y \geq 20\).

So, the answer is no.

Doesthepoint(1, 10) satisfy the inequality y < 7x + 1?

yes or no

To determine if the point (1, 10) satisfies the inequality \( y < 7x + 1 \), we can substitute \( x = 1 \) and see if \( y \) is less than \( 7 \cdot 1 + 1 \).

First, calculate the right side:

\[ 7(1) + 1 = 7 + 1 = 8 \]

Now, we check the inequality:

\[ 10 < 8 \]

This statement is false. Therefore, the point (1, 10) does not satisfy the inequality \( y < 7x + 1 \).

So, the answer is no.

Does(2, 3)maketheinequality2x + 3y < 20true?

To determine if the point (2, 3) satisfies the inequality \(2x + 3y < 20\), we can substitute \(x = 2\) and \(y = 3\) into the inequality.

Calculating the left side:

\[ 2(2) + 3(3) < 20 \]

Now, compute the values:

\[ 4 + 9 < 20 \]

This simplifies to:

\[ 13 < 20 \]

This statement is true. Therefore, the point (2, 3) does satisfy the inequality \(2x + 3y < 20\).

So, the answer is yes.

Is(4, 9)asolutiontotheinequalityy ≤ 2x + 1?

To determine if the point (4, 9) satisfies the inequality \(y \leq 2x + 1\), we can substitute \(x = 4\) and \(y = 9\) into the inequality.

First, calculate the right side:

\[ 2(4) + 1 = 8 + 1 = 9 \]

Now, we check the inequality:

\[ 9 \leq 9 \]

This statement is true. Therefore, the point (4, 9) is a solution to the inequality \(y \leq 2x + 1\).

So, the answer is yes.

Doesthepoint(2, 5)satisfytheinequality14x + 20y ≥ 6?

To determine if the point (2, 5) satisfies the inequality \(14x + 20y \geq 6\), we can substitute \(x = 2\) and \(y = 5\) into the inequality.

Calculating the left side:

\[ 14(2) + 20(5) \geq 6 \]

Now, compute the values:

\[ 28 + 100 \geq 6 \]

This simplifies to:

\[ 128 \geq 6 \]

This statement is true. Therefore, the point (2, 5) does satisfy the inequality \(14x + 20y \geq 6\).

So, the answer is yes.

Does(1, 7)maketheinequalityy < 7x + 10true?

To determine if the point (1, 7) satisfies the inequality \(y < 7x + 10\), we can substitute \(x = 1\) and \(y = 7\) into the inequality.

First, calculate the right side using \(x = 1\):

\[ 7(1) + 10 = 7 + 10 = 17 \]

Now we check the inequality:

\[ 7 < 17 \]

This statement is true. Therefore, the point (1, 7) does satisfy the inequality \(y < 7x + 10\).

So, the answer is yes.

Doesthepoint(1, 1)satisfytheinequality2x + 12y > 16?

To determine if the point (1, 1) satisfies the inequality \(2x + 12y > 16\), we can substitute \(x = 1\) and \(y = 1\) into the inequality.

Calculating the left side:

\[ 2(1) + 12(1) > 16 \]

Now, compute the values:

\[ 2 + 12 > 16 \]

This simplifies to:

\[ 14 > 16 \]

This statement is false. Therefore, the point (1, 1) does not satisfy the inequality \(2x + 12y > 16\).

So, the answer is no.

Is(4, 5)asolutiontotheinequalityy ≥ 7x + 3?

To determine if the point (4, 5) satisfies the inequality \(y \geq 7x + 3\), we can substitute \(x = 4\) and \(y = 5\) into the inequality.

First, calculate the right side:

\[ 7(4) + 3 = 28 + 3 = 31 \]

Now we check the inequality:

\[ 5 \geq 31 \]

This statement is false. Therefore, the point (4, 5) is not a solution to the inequality \(y \geq 7x + 3\).

So, the answer is no.

Does(1, 10)maketheinequalityy > 6x + 1true?

To determine if the point (1, 10) satisfies the inequality \(y > 6x + 1\), we will substitute \(x = 1\) and \(y = 10\) into the inequality.

First, calculate the right side:

\[ 6(1) + 1 = 6 + 1 = 7 \]

Now, check if the inequality holds:

\[ 10 > 7 \]

This statement is true. Therefore, the point (1, 10) does satisfy the inequality \(y > 6x + 1\).

So, the answer is yes.

Is(–7, 7)asolutiontotheinequality
y

1
7
x
+ 8
?

To determine if the point \((-7, 7)\) satisfies the inequality

\[ y \geq \frac{1}{7}x + 8, \]

we can substitute \(x = -7\) and \(y = 7\) into the inequality.

First, calculate the right side:

\[ \frac{1}{7}(-7) + 8 = -1 + 8 = 7. \]

Now we check the inequality:

\[ 7 \geq 7. \]

This statement is true. Therefore, the point \((-7, 7)\) is a solution to the inequality

\[ y \geq \frac{1}{7}x + 8. \]

So, the answer is yes.

Doesthepoint(5, 3)satisfytheinequality2x + 3y > 13?

To determine if the point (5, 3) satisfies the inequality \(2x + 3y > 13\), we can substitute \(x = 5\) and \(y = 3\) into the inequality.

Calculating the left side:

\[ 2(5) + 3(3) > 13 \]

Now, compute the values:

\[ 10 + 9 > 13 \]

This simplifies to:

\[ 19 > 13. \]

This statement is true. Therefore, the point (5, 3) does satisfy the inequality \(2x + 3y > 13\).

So, the answer is yes.

Does(–5, –8)maketheinequalityy < 10true?

To determine if the point \((-5, -8)\) satisfies the inequality \(y < 10\), we can substitute \(y = -8\) into the inequality.

Check the inequality:

\[ -8 < 10. \]

This statement is true. Therefore, the point \((-5, -8)\) does satisfy the inequality \(y < 10\).

So, the answer is yes.

Doesthepoint(–1, 3)satisfytheinequality6x + 6y > 12?

To determine if the point \((-1, 3)\) satisfies the inequality \(6x + 6y > 12\), we can substitute \(x = -1\) and \(y = 3\) into the inequality.

Calculating the left side:

\[ 6(-1) + 6(3) > 12 \]

Now, compute the values:

\[ -6 + 18 > 12 \]

This simplifies to:

\[ 12 > 12. \]

This statement is false since \(12\) is not greater than \(12\). Therefore, the point \((-1, 3)\) does not satisfy the inequality \(6x + 6y > 12\).

So, the answer is no.

Is(5, 1)asolutiontotheinequalityy < 10x + 1?

To determine if the point \((5, 1)\) satisfies the inequality \(y < 10x + 1\), we can substitute \(x = 5\) and \(y = 1\) into the inequality.

First, calculate the right side:

\[ 10(5) + 1 = 50 + 1 = 51. \]

Now we check the inequality:

\[ 1 < 51. \]

This statement is true. Therefore, the point \((5, 1)\) does satisfy the inequality \(y < 10x + 1\).

So, the answer is yes.

Doesthepoint(10, –8)satisfytheinequality5x + 6y ≤ 2?

To determine if the point \((10, -8)\) satisfies the inequality \(5x + 6y \leq 2\), we can substitute \(x = 10\) and \(y = -8\) into the inequality.

Calculating the left side:

\[ 5(10) + 6(-8) \leq 2 \]

Now, compute the values:

\[ 50 - 48 \leq 2 \]

This simplifies to:

\[ 2 \leq 2. \]

The statement is true since \(2\) is equal to \(2\). Therefore, the point \((10, -8)\) does satisfy the inequality \(5x + 6y \leq 2\).

So, the answer is yes.

Does(1, 7)maketheinequalityy ≥ 5x + 2true?

To determine if the point \((1, 7)\) satisfies the inequality \(y \geq 5x + 2\), we can substitute \(x = 1\) and \(y = 7\) into the inequality.

First, calculate the right side:

\[ 5(1) + 2 = 5 + 2 = 7. \]

Now we check the inequality:

\[ 7 \geq 7. \]

This statement is true. Therefore, the point \((1, 7)\) does satisfy the inequality \(y \geq 5x + 2\).

So, the answer is yes.

s(1, 2)asolutiontotheinequality2x + 7y < 18?

To determine if the point \((1, 2)\) satisfies the inequality \(2x + 7y < 18\), we can substitute \(x = 1\) and \(y = 2\) into the inequality.

Calculating the left side:

\[ 2(1) + 7(2) < 18 \]

Now compute the values:

\[ 2 + 14 < 18 \]

This simplifies to:

\[ 16 < 18. \]

This statement is true. Therefore, the point \((1, 2)\) does satisfy the inequality \(2x + 7y < 18\).

So, the answer is yes.

Does(8, –2)maketheinequalityx > –2true?

To determine if the point \((8, -2)\) satisfies the inequality \(x > -2\), we can simply check the value of \(x\).

Here, \(x = 8\).

Now, check the inequality:

\[ 8 > -2. \]

This statement is true. Therefore, the point \((8, -2)\) does satisfy the inequality \(x > -2\).

So, the answer is yes.

Doesthepoint(–2, –5)satisfytheinequality
y

1
2
x
− 4
?

To determine if the point \((-2, -5)\) satisfies the inequality

\[ y \geq \frac{1}{2}x - 4, \]

we will substitute \(x = -2\) and \(y = -5\) into the inequality.

First, calculate the right side:

\[ \frac{1}{2}(-2) - 4 = -1 - 4 = -5. \]

Now we check the inequality:

\[ -5 \geq -5. \]

This statement is true since \(-5\) is equal to \(-5\). Therefore, the point \((-2, -5)\) does satisfy the inequality

\[ y \geq \frac{1}{2}x - 4. \]

So, the answer is yes.

Is(–4, 2)asolutiontotheinequalityy > 4x + 10?

To determine if the point \((-4, 2)\) satisfies the inequality

\[ y > 4x + 10, \]

we can substitute \(x = -4\) and \(y = 2\) into the inequality.

First, calculate the right side:

\[ 4(-4) + 10 = -16 + 10 = -6. \]

Now we check the inequality:

\[ 2 > -6. \]

This statement is true. Therefore, the point \((-4, 2)\) does satisfy the inequality

\[ y > 4x + 10. \]

So, the answer is yes.

Does(–2, –5)maketheinequality2x − 20y ≥ –5true?

To determine if the point \((-2, -5)\) satisfies the inequality

\[ 2x - 20y \geq -5, \]

we can substitute \(x = -2\) and \(y = -5\) into the inequality.

Calculating the left side:

\[ 2(-2) - 20(-5) \geq -5. \]

Now compute the values:

\[ -4 + 100 \geq -5. \]

This simplifies to:

\[ 96 \geq -5. \]

This statement is true. Therefore, the point \((-2, -5)\) does satisfy the inequality

\[ 2x - 20y \geq -5. \]

So, the answer is yes.

Doesthepoint(10, 10)satisfytheinequality20x − 17y ≥ –12?

To determine if the point \((10, 10)\) satisfies the inequality

\[ 20x - 17y \geq -12, \]

we can substitute \(x = 10\) and \(y = 10\) into the inequality.

Calculating the left side:

\[ 20(10) - 17(10) \geq -12. \]

Now compute the values:

\[ 200 - 170 \geq -12. \]

This simplifies to:

\[ 30 \geq -12. \]

This statement is true. Therefore, the point \((10, 10)\) does satisfy the inequality

\[ 20x - 17y \geq -12. \]

So, the answer is yes.

Does(–5, –8)maketheinequalityy < –4true?

To determine if the point \((-5, -8)\) satisfies the inequality

\[ y < -4, \]

we can simply check the value of \(y\).

Here, \(y = -8\).

Now, check the inequality:

\[ -8 < -4. \]

This statement is true. Therefore, the point \((-5, -8)\) does satisfy the inequality \(y < -4\).

So, the answer is yes.

Doesthepoint(2, –2)satisfytheinequalityy ≤ 3x − 8?

To determine if the point \((2, -2)\) satisfies the inequality

\[ y \leq 3x - 8, \]

we can substitute \(x = 2\) and \(y = -2\) into the inequality.

First, calculate the right side:

\[ 3(2) - 8 = 6 - 8 = -2. \]

Now we check the inequality:

\[ -2 \leq -2. \]

This statement is true since \(-2\) is equal to \(-2\). Therefore, the point \((2, -2)\) does satisfy the inequality

\[ y \leq 3x - 8. \]

So, the answer is yes.