Is 3(6q-9)+7(q+4)=5(6q+8)-5(q+1) a conditional equation , an identity , or a contradiction

1 answer

3(6q-9)+7(q+4)=5(6q+8)-5(q+1)
18q-27+7q+28 = 30q+40-5q-5
25q+1 = 25q+35
now what do you think?