To check if (-2, 6) is a solution to the system of equations x + 2y = 10 and 3x + y = 0, we substitute the x and y values of (-2, 6) into both equations and see if the equations hold true.
For the first equation:
(-2) + 2(6) = 10
-2 + 12 = 10
10 = 10
The first equation is true when substituting x = -2 and y = 6.
For the second equation:
3(-2) + 6 = 0
-6 + 6 = 0
0 = 0
The second equation is also true when substituting x = -2 and y = 6.
Since both equations are true when substituting x = -2 and y = 6, (-2, 6) is a solution to the system of equations x + 2y = 10 and 3x + y = 0.
Is (−2, 6) a solution to the system of these linear equations: x+2y=10 and 3x+y=0 ? Why?(1 point)
1 answer